7(a+1)-3a=4+4(2a-1)

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Solution for 7(a+1)-3a=4+4(2a-1) equation:



7(a+1)-3a=4+4(2a-1)
We move all terms to the left:
7(a+1)-3a-(4+4(2a-1))=0
We add all the numbers together, and all the variables
-3a+7(a+1)-(4+4(2a-1))=0
We multiply parentheses
-3a+7a-(4+4(2a-1))+7=0
We calculate terms in parentheses: -(4+4(2a-1)), so:
4+4(2a-1)
determiningTheFunctionDomain 4(2a-1)+4
We multiply parentheses
8a-4+4
We add all the numbers together, and all the variables
8a
Back to the equation:
-(8a)
We add all the numbers together, and all the variables
-4a+7=0
We move all terms containing a to the left, all other terms to the right
-4a=-7
a=-7/-4
a=1+3/4

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