7(a+1)-3a=4+4(2a-1)

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Solution for 7(a+1)-3a=4+4(2a-1) equation: 



7(a+1)-3a=4+4(2a-1)

We move all terms to the left:

7(a+1)-3a-(4+4(2a-1))=0

We add all the numbers together, and all the variables

-3a+7(a+1)-(4+4(2a-1))=0

We multiply parentheses

-3a+7a-(4+4(2a-1))+7=0



We calculate terms in parentheses: -(4+4(2a-1)), so:

4+4(2a-1)

determiningTheFunctionDomain
4(2a-1)+4

We multiply parentheses

8a-4+4

We add all the numbers together, and all the variables

8a

Back to the equation:

-(8a)



We add all the numbers together, and all the variables

-4a+7=0

We move all terms containing a to the left, all other terms to the right

-4a=-7

a=-7/-4

a=1+3/4

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