7(a+2)=3(2a+10)

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Solution for 7(a+2)=3(2a+10) equation: 



7(a+2)=3(2a+10)

We move all terms to the left:

7(a+2)-(3(2a+10))=0

We multiply parentheses

7a-(3(2a+10))+14=0



We calculate terms in parentheses: -(3(2a+10)), so:

3(2a+10)

We multiply parentheses

6a+30

Back to the equation:

-(6a+30)



We get rid of parentheses

7a-6a-30+14=0

We add all the numbers together, and all the variables

a-16=0

We move all terms containing a to the left, all other terms to the right

a=16

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