7(a+4)-10=3a+20+4a-2

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Solution for 7(a+4)-10=3a+20+4a-2 equation: 



7(a+4)-10=3a+20+4a-2

We move all terms to the left:

7(a+4)-10-(3a+20+4a-2)=0

We add all the numbers together, and all the variables

7(a+4)-(7a+18)-10=0

We multiply parentheses

7a-(7a+18)+28-10=0

We get rid of parentheses

7a-7a-18+28-10=0

We add all the numbers together, and all the variables

=0

a=0/1

a=0

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