7(a+4)=4(a+3)-4a

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Solution for 7(a+4)=4(a+3)-4a equation: 



7(a+4)=4(a+3)-4a

We move all terms to the left:

7(a+4)-(4(a+3)-4a)=0

We multiply parentheses

7a-(4(a+3)-4a)+28=0



We calculate terms in parentheses: -(4(a+3)-4a), so:

4(a+3)-4a

We add all the numbers together, and all the variables

-4a+4(a+3)

We multiply parentheses

-4a+4a+12

We add all the numbers together, and all the variables

12

Back to the equation:

-(12)



We add all the numbers together, and all the variables

7a+16=0

We move all terms containing a to the left, all other terms to the right

7a=-16

a=-16/7

a=-2+2/7

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