7(a-3)=4a+2(a+1)

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Solution for 7(a-3)=4a+2(a+1) equation: 



7(a-3)=4a+2(a+1)

We move all terms to the left:

7(a-3)-(4a+2(a+1))=0

We multiply parentheses

7a-(4a+2(a+1))-21=0



We calculate terms in parentheses: -(4a+2(a+1)), so:

4a+2(a+1)

We multiply parentheses

4a+2a+2

We add all the numbers together, and all the variables

6a+2

Back to the equation:

-(6a+2)



We get rid of parentheses

7a-6a-2-21=0

We add all the numbers together, and all the variables

a-23=0

We move all terms containing a to the left, all other terms to the right

a=23

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