7(a-4)-2=19+3(a+3)

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Solution for 7(a-4)-2=19+3(a+3) equation: 



7(a-4)-2=19+3(a+3)

We move all terms to the left:

7(a-4)-2-(19+3(a+3))=0

We multiply parentheses

7a-(19+3(a+3))-28-2=0



We calculate terms in parentheses: -(19+3(a+3)), so:

19+3(a+3)

determiningTheFunctionDomain
3(a+3)+19

We multiply parentheses

3a+9+19

We add all the numbers together, and all the variables

3a+28

Back to the equation:

-(3a+28)



We add all the numbers together, and all the variables

7a-(3a+28)-30=0

We get rid of parentheses

7a-3a-28-30=0

We add all the numbers together, and all the variables

4a-58=0

We move all terms containing a to the left, all other terms to the right

4a=58

a=58/4

a=14+1/2

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