7(a-4)-2a=18+3(a+3)

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Solution for 7(a-4)-2a=18+3(a+3) equation: 



7(a-4)-2a=18+3(a+3)

We move all terms to the left:

7(a-4)-2a-(18+3(a+3))=0

We add all the numbers together, and all the variables

-2a+7(a-4)-(18+3(a+3))=0

We multiply parentheses

-2a+7a-(18+3(a+3))-28=0



We calculate terms in parentheses: -(18+3(a+3)), so:

18+3(a+3)

determiningTheFunctionDomain
3(a+3)+18

We multiply parentheses

3a+9+18

We add all the numbers together, and all the variables

3a+27

Back to the equation:

-(3a+27)



We add all the numbers together, and all the variables

5a-(3a+27)-28=0

We get rid of parentheses

5a-3a-27-28=0

We add all the numbers together, and all the variables

2a-55=0

We move all terms containing a to the left, all other terms to the right

2a=55

a=55/2

a=27+1/2

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