7(a-4)=3(2a+5)

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Solution for 7(a-4)=3(2a+5) equation: 



7(a-4)=3(2a+5)

We move all terms to the left:

7(a-4)-(3(2a+5))=0

We multiply parentheses

7a-(3(2a+5))-28=0



We calculate terms in parentheses: -(3(2a+5)), so:

3(2a+5)

We multiply parentheses

6a+15

Back to the equation:

-(6a+15)



We get rid of parentheses

7a-6a-15-28=0

We add all the numbers together, and all the variables

a-43=0

We move all terms containing a to the left, all other terms to the right

a=43

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