7(a-5)+19=3(a-4)

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Solution for 7(a-5)+19=3(a-4) equation:


Simplifying
7(a + -5) + 19 = 3(a + -4)

Reorder the terms:
7(-5 + a) + 19 = 3(a + -4)
(-5 * 7 + a * 7) + 19 = 3(a + -4)
(-35 + 7a) + 19 = 3(a + -4)

Reorder the terms:
-35 + 19 + 7a = 3(a + -4)

Combine like terms: -35 + 19 = -16
-16 + 7a = 3(a + -4)

Reorder the terms:
-16 + 7a = 3(-4 + a)
-16 + 7a = (-4 * 3 + a * 3)
-16 + 7a = (-12 + 3a)

Solving
-16 + 7a = -12 + 3a

Solving for variable 'a'.

Move all terms containing a to the left, all other terms to the right.

Add '-3a' to each side of the equation.
-16 + 7a + -3a = -12 + 3a + -3a

Combine like terms: 7a + -3a = 4a
-16 + 4a = -12 + 3a + -3a

Combine like terms: 3a + -3a = 0
-16 + 4a = -12 + 0
-16 + 4a = -12

Add '16' to each side of the equation.
-16 + 16 + 4a = -12 + 16

Combine like terms: -16 + 16 = 0
0 + 4a = -12 + 16
4a = -12 + 16

Combine like terms: -12 + 16 = 4
4a = 4

Divide each side by '4'.
a = 1

Simplifying
a = 1

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