7(a-6)+12=5(a-4)

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Solution for 7(a-6)+12=5(a-4) equation: 



7(a-6)+12=5(a-4)

We move all terms to the left:

7(a-6)+12-(5(a-4))=0

We multiply parentheses

7a-(5(a-4))-42+12=0



We calculate terms in parentheses: -(5(a-4)), so:

5(a-4)

We multiply parentheses

5a-20

Back to the equation:

-(5a-20)



We add all the numbers together, and all the variables

7a-(5a-20)-30=0

We get rid of parentheses

7a-5a+20-30=0

We add all the numbers together, and all the variables

2a-10=0

We move all terms containing a to the left, all other terms to the right

2a=10

a=10/2

a=5

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