7(a-6)+16=3(a-6)

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Solution for 7(a-6)+16=3(a-6) equation:



7(a-6)+16=3(a-6)
We move all terms to the left:
7(a-6)+16-(3(a-6))=0
We multiply parentheses
7a-(3(a-6))-42+16=0
We calculate terms in parentheses: -(3(a-6)), so:
3(a-6)
We multiply parentheses
3a-18
Back to the equation:
-(3a-18)
We add all the numbers together, and all the variables
7a-(3a-18)-26=0
We get rid of parentheses
7a-3a+18-26=0
We add all the numbers together, and all the variables
4a-8=0
We move all terms containing a to the left, all other terms to the right
4a=8
a=8/4
a=2

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