7(b+1)=6b+2+6

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Solution for 7(b+1)=6b+2+6 equation: 



7(b+1)=6b+2+6

We move all terms to the left:

7(b+1)-(6b+2+6)=0

We add all the numbers together, and all the variables

7(b+1)-(6b+8)=0

We multiply parentheses

7b-(6b+8)+7=0

We get rid of parentheses

7b-6b-8+7=0

We add all the numbers together, and all the variables

b-1=0

We move all terms containing b to the left, all other terms to the right

b=1

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