7(b+2)+47=2(b+10)

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Solution for 7(b+2)+47=2(b+10) equation: 



7(b+2)+47=2(b+10)

We move all terms to the left:

7(b+2)+47-(2(b+10))=0

We multiply parentheses

7b-(2(b+10))+14+47=0



We calculate terms in parentheses: -(2(b+10)), so:

2(b+10)

We multiply parentheses

2b+20

Back to the equation:

-(2b+20)



We add all the numbers together, and all the variables

7b-(2b+20)+61=0

We get rid of parentheses

7b-2b-20+61=0

We add all the numbers together, and all the variables

5b+41=0

We move all terms containing b to the left, all other terms to the right

5b=-41

b=-41/5

b=-8+1/5

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