7(b+2)-46=2(b+10)

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Solution for 7(b+2)-46=2(b+10) equation:


Simplifying
7(b + 2) + -46 = 2(b + 10)

Reorder the terms:
7(2 + b) + -46 = 2(b + 10)
(2 * 7 + b * 7) + -46 = 2(b + 10)
(14 + 7b) + -46 = 2(b + 10)

Reorder the terms:
14 + -46 + 7b = 2(b + 10)

Combine like terms: 14 + -46 = -32
-32 + 7b = 2(b + 10)

Reorder the terms:
-32 + 7b = 2(10 + b)
-32 + 7b = (10 * 2 + b * 2)
-32 + 7b = (20 + 2b)

Solving
-32 + 7b = 20 + 2b

Solving for variable 'b'.

Move all terms containing b to the left, all other terms to the right.

Add '-2b' to each side of the equation.
-32 + 7b + -2b = 20 + 2b + -2b

Combine like terms: 7b + -2b = 5b
-32 + 5b = 20 + 2b + -2b

Combine like terms: 2b + -2b = 0
-32 + 5b = 20 + 0
-32 + 5b = 20

Add '32' to each side of the equation.
-32 + 32 + 5b = 20 + 32

Combine like terms: -32 + 32 = 0
0 + 5b = 20 + 32
5b = 20 + 32

Combine like terms: 20 + 32 = 52
5b = 52

Divide each side by '5'.
b = 10.4

Simplifying
b = 10.4

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