7(b+3)-1=7(b+4)-8

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Solution for 7(b+3)-1=7(b+4)-8 equation: 


Simplifying
7(b + 3) + -1 = 7(b + 4) + -8

Reorder the terms:
7(3 + b) + -1 = 7(b + 4) + -8
(3 * 7 + b * 7) + -1 = 7(b + 4) + -8
(21 + 7b) + -1 = 7(b + 4) + -8

Reorder the terms:
21 + -1 + 7b = 7(b + 4) + -8

Combine like terms: 21 + -1 = 20
20 + 7b = 7(b + 4) + -8

Reorder the terms:
20 + 7b = 7(4 + b) + -8
20 + 7b = (4 * 7 + b * 7) + -8
20 + 7b = (28 + 7b) + -8

Reorder the terms:
20 + 7b = 28 + -8 + 7b

Combine like terms: 28 + -8 = 20
20 + 7b = 20 + 7b

Add '-20' to each side of the equation.
20 + -20 + 7b = 20 + -20 + 7b

Combine like terms: 20 + -20 = 0
0 + 7b = 20 + -20 + 7b
7b = 20 + -20 + 7b

Combine like terms: 20 + -20 = 0
7b = 0 + 7b
7b = 7b

Add '-7b' to each side of the equation.
7b + -7b = 7b + -7b

Combine like terms: 7b + -7b = 0
0 = 7b + -7b

Combine like terms: 7b + -7b = 0
0 = 0

Solving
0 = 0

Couldn't find a variable to solve for.

This equation is an identity, all real numbers are solutions.

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