7(b+3)-5(b-3)=2(b-20)-4

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Solution for 7(b+3)-5(b-3)=2(b-20)-4 equation:


Simplifying
7(b + 3) + -5(b + -3) = 2(b + -20) + -4

Reorder the terms:
7(3 + b) + -5(b + -3) = 2(b + -20) + -4
(3 * 7 + b * 7) + -5(b + -3) = 2(b + -20) + -4
(21 + 7b) + -5(b + -3) = 2(b + -20) + -4

Reorder the terms:
21 + 7b + -5(-3 + b) = 2(b + -20) + -4
21 + 7b + (-3 * -5 + b * -5) = 2(b + -20) + -4
21 + 7b + (15 + -5b) = 2(b + -20) + -4

Reorder the terms:
21 + 15 + 7b + -5b = 2(b + -20) + -4

Combine like terms: 21 + 15 = 36
36 + 7b + -5b = 2(b + -20) + -4

Combine like terms: 7b + -5b = 2b
36 + 2b = 2(b + -20) + -4

Reorder the terms:
36 + 2b = 2(-20 + b) + -4
36 + 2b = (-20 * 2 + b * 2) + -4
36 + 2b = (-40 + 2b) + -4

Reorder the terms:
36 + 2b = -40 + -4 + 2b

Combine like terms: -40 + -4 = -44
36 + 2b = -44 + 2b

Add '-2b' to each side of the equation.
36 + 2b + -2b = -44 + 2b + -2b

Combine like terms: 2b + -2b = 0
36 + 0 = -44 + 2b + -2b
36 = -44 + 2b + -2b

Combine like terms: 2b + -2b = 0
36 = -44 + 0
36 = -44

Solving
36 = -44

Couldn't find a variable to solve for.

This equation is invalid, the left and right sides are not equal, therefore there is no solution.

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