7(b+3)=1+7b-(-4)

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Solution for 7(b+3)=1+7b-(-4) equation:



7(b+3)=1+7b-(-4)
We move all terms to the left:
7(b+3)-(1+7b-(-4))=0
We multiply parentheses
7b-(1+7b-(-4))+21=0
We calculate terms in parentheses: -(1+7b-(-4)), so:
1+7b-(-4)
determiningTheFunctionDomain 7b+1-(-4)
We add all the numbers together, and all the variables
7b+5
Back to the equation:
-(7b+5)
We get rid of parentheses
7b-7b-5+21=0
We add all the numbers together, and all the variables
16!=0
There is no solution for this equation

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