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7(b+3)=10b+9-3(b-4)
We move all terms to the left:
7(b+3)-(10b+9-3(b-4))=0
We multiply parentheses
7b-(10b+9-3(b-4))+21=0
We calculate terms in parentheses: -(10b+9-3(b-4)), so:We get rid of parentheses
10b+9-3(b-4)
determiningTheFunctionDomain 10b-3(b-4)+9
We multiply parentheses
10b-3b+12+9
We add all the numbers together, and all the variables
7b+21
Back to the equation:
-(7b+21)
7b-7b-21+21=0
We add all the numbers together, and all the variables
=0
b=0/1
b=0
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