7(b+3)=2(b-3)

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Solution for 7(b+3)=2(b-3) equation: 



7(b+3)=2(b-3)

We move all terms to the left:

7(b+3)-(2(b-3))=0

We multiply parentheses

7b-(2(b-3))+21=0



We calculate terms in parentheses: -(2(b-3)), so:

2(b-3)

We multiply parentheses

2b-6

Back to the equation:

-(2b-6)



We get rid of parentheses

7b-2b+6+21=0

We add all the numbers together, and all the variables

5b+27=0

We move all terms containing b to the left, all other terms to the right

5b=-27

b=-27/5

b=-5+2/5

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