7(b+3)=2(b-3)

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Solution for 7(b+3)=2(b-3) equation:



7(b+3)=2(b-3)
We move all terms to the left:
7(b+3)-(2(b-3))=0
We multiply parentheses
7b-(2(b-3))+21=0
We calculate terms in parentheses: -(2(b-3)), so:
2(b-3)
We multiply parentheses
2b-6
Back to the equation:
-(2b-6)
We get rid of parentheses
7b-2b+6+21=0
We add all the numbers together, and all the variables
5b+27=0
We move all terms containing b to the left, all other terms to the right
5b=-27
b=-27/5
b=-5+2/5

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