7(b+5)=6/7(7b+14)

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Solution for 7(b+5)=6/7(7b+14) equation: 



7(b+5)=6/7(7b+14)

We move all terms to the left:

7(b+5)-(6/7(7b+14))=0



Domain of the equation: 7(7b+14))!=0

b∈R



We multiply parentheses

7b-(6/7(7b+14))+35=0

We multiply all the terms by the denominator


7b*7(7b+14))-(6+35*7(7b+14))=0

Wy multiply elements

49b^2(7+245b(7=0

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