7(b-2)=-32+b

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Solution for 7(b-2)=-32+b equation: 



7(b-2)=-32+b

We move all terms to the left:

7(b-2)-(-32+b)=0

We add all the numbers together, and all the variables

7(b-2)-(b-32)=0

We multiply parentheses

7b-(b-32)-14=0

We get rid of parentheses

7b-b+32-14=0

We add all the numbers together, and all the variables

6b+18=0

We move all terms containing b to the left, all other terms to the right

6b=-18

b=-18/6

b=-3

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