7(b-3)=12(b+12)

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Solution for 7(b-3)=12(b+12) equation: 



7(b-3)=12(b+12)

We move all terms to the left:

7(b-3)-(12(b+12))=0

We multiply parentheses

7b-(12(b+12))-21=0



We calculate terms in parentheses: -(12(b+12)), so:

12(b+12)

We multiply parentheses

12b+144

Back to the equation:

-(12b+144)



We get rid of parentheses

7b-12b-144-21=0

We add all the numbers together, and all the variables

-5b-165=0

We move all terms containing b to the left, all other terms to the right

-5b=165

b=165/-5

b=-33

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