7(b-3)=2(7b+3)

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Solution for 7(b-3)=2(7b+3) equation: 



7(b-3)=2(7b+3)

We move all terms to the left:

7(b-3)-(2(7b+3))=0

We multiply parentheses

7b-(2(7b+3))-21=0



We calculate terms in parentheses: -(2(7b+3)), so:

2(7b+3)

We multiply parentheses

14b+6

Back to the equation:

-(14b+6)



We get rid of parentheses

7b-14b-6-21=0

We add all the numbers together, and all the variables

-7b-27=0

We move all terms containing b to the left, all other terms to the right

-7b=27

b=27/-7

b=-3+6/7

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