7(b-3)=2(7b+3)

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Solution for 7(b-3)=2(7b+3) equation:



7(b-3)=2(7b+3)
We move all terms to the left:
7(b-3)-(2(7b+3))=0
We multiply parentheses
7b-(2(7b+3))-21=0
We calculate terms in parentheses: -(2(7b+3)), so:
2(7b+3)
We multiply parentheses
14b+6
Back to the equation:
-(14b+6)
We get rid of parentheses
7b-14b-6-21=0
We add all the numbers together, and all the variables
-7b-27=0
We move all terms containing b to the left, all other terms to the right
-7b=27
b=27/-7
b=-3+6/7

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