7(b-3)=2(b+12)

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Solution for 7(b-3)=2(b+12) equation: 



7(b-3)=2(b+12)

We move all terms to the left:

7(b-3)-(2(b+12))=0

We multiply parentheses

7b-(2(b+12))-21=0



We calculate terms in parentheses: -(2(b+12)), so:

2(b+12)

We multiply parentheses

2b+24

Back to the equation:

-(2b+24)



We get rid of parentheses

7b-2b-24-21=0

We add all the numbers together, and all the variables

5b-45=0

We move all terms containing b to the left, all other terms to the right

5b=45

b=45/5

b=9

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