7(b-3)=2(b+13)

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Solution for 7(b-3)=2(b+13) equation: 



7(b-3)=2(b+13)

We move all terms to the left:

7(b-3)-(2(b+13))=0

We multiply parentheses

7b-(2(b+13))-21=0



We calculate terms in parentheses: -(2(b+13)), so:

2(b+13)

We multiply parentheses

2b+26

Back to the equation:

-(2b+26)



We get rid of parentheses

7b-2b-26-21=0

We add all the numbers together, and all the variables

5b-47=0

We move all terms containing b to the left, all other terms to the right

5b=47

b=47/5

b=9+2/5

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