7(b-3)=8b+2+3

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Solution for 7(b-3)=8b+2+3 equation:



7(b-3)=8b+2+3
We move all terms to the left:
7(b-3)-(8b+2+3)=0
We add all the numbers together, and all the variables
7(b-3)-(8b+5)=0
We multiply parentheses
7b-(8b+5)-21=0
We get rid of parentheses
7b-8b-5-21=0
We add all the numbers together, and all the variables
-1b-26=0
We move all terms containing b to the left, all other terms to the right
-b=26
b=26/-1
b=-26

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