7(b-4)-5(b+2)=0

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Solution for 7(b-4)-5(b+2)=0 equation:


Simplifying
7(b + -4) + -5(b + 2) = 0

Reorder the terms:
7(-4 + b) + -5(b + 2) = 0
(-4 * 7 + b * 7) + -5(b + 2) = 0
(-28 + 7b) + -5(b + 2) = 0

Reorder the terms:
-28 + 7b + -5(2 + b) = 0
-28 + 7b + (2 * -5 + b * -5) = 0
-28 + 7b + (-10 + -5b) = 0

Reorder the terms:
-28 + -10 + 7b + -5b = 0

Combine like terms: -28 + -10 = -38
-38 + 7b + -5b = 0

Combine like terms: 7b + -5b = 2b
-38 + 2b = 0

Solving
-38 + 2b = 0

Solving for variable 'b'.

Move all terms containing b to the left, all other terms to the right.

Add '38' to each side of the equation.
-38 + 38 + 2b = 0 + 38

Combine like terms: -38 + 38 = 0
0 + 2b = 0 + 38
2b = 0 + 38

Combine like terms: 0 + 38 = 38
2b = 38

Divide each side by '2'.
b = 19

Simplifying
b = 19

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