7(b-4)-5=37+6b

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Solution for 7(b-4)-5=37+6b equation: 



7(b-4)-5=37+6b

We move all terms to the left:

7(b-4)-5-(37+6b)=0

We add all the numbers together, and all the variables

7(b-4)-(6b+37)-5=0

We multiply parentheses

7b-(6b+37)-28-5=0

We get rid of parentheses

7b-6b-37-28-5=0

We add all the numbers together, and all the variables

b-70=0

We move all terms containing b to the left, all other terms to the right

b=70

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