7(b-4)=(b-2)

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Solution for 7(b-4)=(b-2) equation: 



7(b-4)=(b-2)

We move all terms to the left:

7(b-4)-((b-2))=0

We multiply parentheses

7b-((b-2))-28=0



We calculate terms in parentheses: -((b-2)), so:

(b-2)

We get rid of parentheses

b-2

Back to the equation:

-(b-2)



We get rid of parentheses

7b-b+2-28=0

We add all the numbers together, and all the variables

6b-26=0

We move all terms containing b to the left, all other terms to the right

6b=26

b=26/6

b=4+1/3

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