7(b-4)=5(b-1)

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Solution for 7(b-4)=5(b-1) equation: 



7(b-4)=5(b-1)

We move all terms to the left:

7(b-4)-(5(b-1))=0

We multiply parentheses

7b-(5(b-1))-28=0



We calculate terms in parentheses: -(5(b-1)), so:

5(b-1)

We multiply parentheses

5b-5

Back to the equation:

-(5b-5)



We get rid of parentheses

7b-5b+5-28=0

We add all the numbers together, and all the variables

2b-23=0

We move all terms containing b to the left, all other terms to the right

2b=23

b=23/2

b=11+1/2

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