7(b-4)=7b-28

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Solution for 7(b-4)=7b-28 equation: 



7(b-4)=7b-28

We move all terms to the left:

7(b-4)-(7b-28)=0

We multiply parentheses

7b-(7b-28)-28=0

We get rid of parentheses

7b-7b+28-28=0

We add all the numbers together, and all the variables

=0

b=0/1

b=0

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