7(b-5)+5(6+4)=45

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Solution for 7(b-5)+5(6+4)=45 equation: 



7(b-5)+5(6+4)=45

We move all terms to the left:

7(b-5)+5(6+4)-(45)=0

determiningTheFunctionDomain
7(b-5)-45+5(6+4)=0

We add all the numbers together, and all the variables

7(b-5)-45+510=0

We add all the numbers together, and all the variables

7(b-5)+465=0

We multiply parentheses

7b-35+465=0

We add all the numbers together, and all the variables

7b+430=0

We move all terms containing b to the left, all other terms to the right

7b=-430

b=-430/7

b=-61+3/7

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