7(b-8)=3b+12

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Solution for 7(b-8)=3b+12 equation:



7(b-8)=3b+12
We move all terms to the left:
7(b-8)-(3b+12)=0
We multiply parentheses
7b-(3b+12)-56=0
We get rid of parentheses
7b-3b-12-56=0
We add all the numbers together, and all the variables
4b-68=0
We move all terms containing b to the left, all other terms to the right
4b=68
b=68/4
b=17

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