7(b-8)=b3(b+12)

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Solution for 7(b-8)=b3(b+12) equation:



7(b-8)=b3(b+12)
We move all terms to the left:
7(b-8)-(b3(b+12))=0
We multiply parentheses
7b-(b3(b+12))-56=0
We calculate terms in parentheses: -(b3(b+12)), so:
b3(b+12)
We multiply parentheses
b^4+12b^3
We do not support ebpression: b^4

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