7(c+1)+11=5(3c-1)-8c

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Solution for 7(c+1)+11=5(3c-1)-8c equation:


Simplifying
7(c + 1) + 11 = 5(3c + -1) + -8c

Reorder the terms:
7(1 + c) + 11 = 5(3c + -1) + -8c
(1 * 7 + c * 7) + 11 = 5(3c + -1) + -8c
(7 + 7c) + 11 = 5(3c + -1) + -8c

Reorder the terms:
7 + 11 + 7c = 5(3c + -1) + -8c

Combine like terms: 7 + 11 = 18
18 + 7c = 5(3c + -1) + -8c

Reorder the terms:
18 + 7c = 5(-1 + 3c) + -8c
18 + 7c = (-1 * 5 + 3c * 5) + -8c
18 + 7c = (-5 + 15c) + -8c

Combine like terms: 15c + -8c = 7c
18 + 7c = -5 + 7c

Add '-7c' to each side of the equation.
18 + 7c + -7c = -5 + 7c + -7c

Combine like terms: 7c + -7c = 0
18 + 0 = -5 + 7c + -7c
18 = -5 + 7c + -7c

Combine like terms: 7c + -7c = 0
18 = -5 + 0
18 = -5

Solving
18 = -5

Couldn't find a variable to solve for.

This equation is invalid, the left and right sides are not equal, therefore there is no solution.

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