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7(c+1)-4c=13(3c^2)
We move all terms to the left:
7(c+1)-4c-(13(3c^2))=0
determiningTheFunctionDomain 7(c+1)-4c-133c^2=0
We add all the numbers together, and all the variables
-133c^2+7(c+1)-4c=0
We add all the numbers together, and all the variables
-133c^2-4c+7(c+1)=0
We multiply parentheses
-133c^2-4c+7c+7=0
We add all the numbers together, and all the variables
-133c^2+3c+7=0
a = -133; b = 3; c = +7;
Δ = b2-4ac
Δ = 32-4·(-133)·7
Δ = 3733
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$c_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$c_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$c_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(3)-\sqrt{3733}}{2*-133}=\frac{-3-\sqrt{3733}}{-266} $$c_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(3)+\sqrt{3733}}{2*-133}=\frac{-3+\sqrt{3733}}{-266} $
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