7(c+1)=9+5c

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Solution for 7(c+1)=9+5c equation: 



7(c+1)=9+5c

We move all terms to the left:

7(c+1)-(9+5c)=0

We add all the numbers together, and all the variables

7(c+1)-(5c+9)=0

We multiply parentheses

7c-(5c+9)+7=0

We get rid of parentheses

7c-5c-9+7=0

We add all the numbers together, and all the variables

2c-2=0

We move all terms containing c to the left, all other terms to the right

2c=2

c=2/2

c=1

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