7(c+2)+4c-41=2c

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Solution for 7(c+2)+4c-41=2c equation: 



7(c+2)+4c-41=2c

We move all terms to the left:

7(c+2)+4c-41-(2c)=0

We add all the numbers together, and all the variables

2c+7(c+2)-41=0

We multiply parentheses

2c+7c+14-41=0

We add all the numbers together, and all the variables

9c-27=0

We move all terms containing c to the left, all other terms to the right

9c=27

c=27/9

c=3

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