7(c+5)=28

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Solution for 7(c+5)=28 equation: 



7(c+5)=28

We move all terms to the left:

7(c+5)-(28)=0

We multiply parentheses

7c+35-28=0

We add all the numbers together, and all the variables

7c+7=0

We move all terms containing c to the left, all other terms to the right

7c=-7

c=-7/7

c=-1

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