7(c-2)+4=3+c-13

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Solution for 7(c-2)+4=3+c-13 equation: 



7(c-2)+4=3+c-13

We move all terms to the left:

7(c-2)+4-(3+c-13)=0

We add all the numbers together, and all the variables

7(c-2)-(c-10)+4=0

We multiply parentheses

7c-(c-10)-14+4=0

We get rid of parentheses

7c-c+10-14+4=0

We add all the numbers together, and all the variables

6c=0

c=0/6

c=0

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