7(c-3)+8=2+c-15

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Solution for 7(c-3)+8=2+c-15 equation: 



7(c-3)+8=2+c-15

We move all terms to the left:

7(c-3)+8-(2+c-15)=0

We add all the numbers together, and all the variables

7(c-3)-(c-13)+8=0

We multiply parentheses

7c-(c-13)-21+8=0

We get rid of parentheses

7c-c+13-21+8=0

We add all the numbers together, and all the variables

6c=0

c=0/6

c=0

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