7(c-3)+9=6-c-18

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Solution for 7(c-3)+9=6-c-18 equation:


Simplifying
7(c + -3) + 9 = 6 + -1c + -18

Reorder the terms:
7(-3 + c) + 9 = 6 + -1c + -18
(-3 * 7 + c * 7) + 9 = 6 + -1c + -18
(-21 + 7c) + 9 = 6 + -1c + -18

Reorder the terms:
-21 + 9 + 7c = 6 + -1c + -18

Combine like terms: -21 + 9 = -12
-12 + 7c = 6 + -1c + -18

Reorder the terms:
-12 + 7c = 6 + -18 + -1c

Combine like terms: 6 + -18 = -12
-12 + 7c = -12 + -1c

Add '12' to each side of the equation.
-12 + 12 + 7c = -12 + 12 + -1c

Combine like terms: -12 + 12 = 0
0 + 7c = -12 + 12 + -1c
7c = -12 + 12 + -1c

Combine like terms: -12 + 12 = 0
7c = 0 + -1c
7c = -1c

Solving
7c = -1c

Solving for variable 'c'.

Move all terms containing c to the left, all other terms to the right.

Add 'c' to each side of the equation.
7c + c = -1c + c

Combine like terms: 7c + c = 8c
8c = -1c + c

Combine like terms: -1c + c = 0
8c = 0

Divide each side by '8'.
c = 0

Simplifying
c = 0

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