7(c-3)/6=2c-1

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Solution for 7(c-3)/6=2c-1 equation:



7(c-3)/6=2c-1
We move all terms to the left:
7(c-3)/6-(2c-1)=0
We get rid of parentheses
7(c-3)/6-2c+1=0
We multiply all the terms by the denominator
7(c-3)-2c*6+1*6=0
We add all the numbers together, and all the variables
7(c-3)-2c*6+6=0
We multiply parentheses
7c-2c*6-21+6=0
Wy multiply elements
7c-12c-21+6=0
We add all the numbers together, and all the variables
-5c-15=0
We move all terms containing c to the left, all other terms to the right
-5c=15
c=15/-5
c=-3

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