7(c-3)=5(c+3)

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Solution for 7(c-3)=5(c+3) equation: 



7(c-3)=5(c+3)

We move all terms to the left:

7(c-3)-(5(c+3))=0

We multiply parentheses

7c-(5(c+3))-21=0



We calculate terms in parentheses: -(5(c+3)), so:

5(c+3)

We multiply parentheses

5c+15

Back to the equation:

-(5c+15)



We get rid of parentheses

7c-5c-15-21=0

We add all the numbers together, and all the variables

2c-36=0

We move all terms containing c to the left, all other terms to the right

2c=36

c=36/2

c=18

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