7(c-3)=7-2(3c+1)

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Solution for 7(c-3)=7-2(3c+1) equation: 



7(c-3)=7-2(3c+1)

We move all terms to the left:

7(c-3)-(7-2(3c+1))=0

We multiply parentheses

7c-(7-2(3c+1))-21=0



We calculate terms in parentheses: -(7-2(3c+1)), so:

7-2(3c+1)

determiningTheFunctionDomain
-2(3c+1)+7

We multiply parentheses

-6c-2+7

We add all the numbers together, and all the variables

-6c+5

Back to the equation:

-(-6c+5)



We get rid of parentheses

7c+6c-5-21=0

We add all the numbers together, and all the variables

13c-26=0

We move all terms containing c to the left, all other terms to the right

13c=26

c=26/13

c=2

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