7(c-4)+4=2+c-26

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Solution for 7(c-4)+4=2+c-26 equation: 



7(c-4)+4=2+c-26

We move all terms to the left:

7(c-4)+4-(2+c-26)=0

We add all the numbers together, and all the variables

7(c-4)-(c-24)+4=0

We multiply parentheses

7c-(c-24)-28+4=0

We get rid of parentheses

7c-c+24-28+4=0

We add all the numbers together, and all the variables

6c=0

c=0/6

c=0

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