7(c-4)+5=3+c-26

Solution for 7(c-4)+5=3+c-26 equation:

Simplifying
7(c + -4) + 5 = 3 + c + -26

Reorder the terms:
7(-4 + c) + 5 = 3 + c + -26
(-4 * 7 + c * 7) + 5 = 3 + c + -26
(-28 + 7c) + 5 = 3 + c + -26

Reorder the terms:
-28 + 5 + 7c = 3 + c + -26

Combine like terms: -28 + 5 = -23
-23 + 7c = 3 + c + -26

Reorder the terms:
-23 + 7c = 3 + -26 + c

Combine like terms: 3 + -26 = -23
-23 + 7c = -23 + c

Add '23' to each side of the equation.
-23 + 23 + 7c = -23 + 23 + c

Combine like terms: -23 + 23 = 0
0 + 7c = -23 + 23 + c
7c = -23 + 23 + c

Combine like terms: -23 + 23 = 0
7c = 0 + c
7c = c

Solving
7c = c

Solving for variable 'c'.

Move all terms containing c to the left, all other terms to the right.

Add '-1c' to each side of the equation.
7c + -1c = c + -1c

Combine like terms: 7c + -1c = 6c
6c = c + -1c

Combine like terms: c + -1c = 0
6c = 0

Divide each side by '6'.
c = 0

Simplifying
c = 0