7(c-4)+6=c+20

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Solution for 7(c-4)+6=c+20 equation: 



7(c-4)+6=c+20

We move all terms to the left:

7(c-4)+6-(c+20)=0

We multiply parentheses

7c-(c+20)-28+6=0

We get rid of parentheses

7c-c-20-28+6=0

We add all the numbers together, and all the variables

6c-42=0

We move all terms containing c to the left, all other terms to the right

6c=42

c=42/6

c=7

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