7(c-5)+5=3+c-33

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Solution for 7(c-5)+5=3+c-33 equation: 



7(c-5)+5=3+c-33

We move all terms to the left:

7(c-5)+5-(3+c-33)=0

We add all the numbers together, and all the variables

7(c-5)-(c-30)+5=0

We multiply parentheses

7c-(c-30)-35+5=0

We get rid of parentheses

7c-c+30-35+5=0

We add all the numbers together, and all the variables

6c=0

c=0/6

c=0

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