7(c-5)+6=2+c-31

Solution for 7(c-5)+6=2+c-31 equation:

Simplifying
7(c + -5) + 6 = 2 + c + -31

Reorder the terms:
7(-5 + c) + 6 = 2 + c + -31
(-5 * 7 + c * 7) + 6 = 2 + c + -31
(-35 + 7c) + 6 = 2 + c + -31

Reorder the terms:
-35 + 6 + 7c = 2 + c + -31

Combine like terms: -35 + 6 = -29
-29 + 7c = 2 + c + -31

Reorder the terms:
-29 + 7c = 2 + -31 + c

Combine like terms: 2 + -31 = -29
-29 + 7c = -29 + c

Add '29' to each side of the equation.
-29 + 29 + 7c = -29 + 29 + c

Combine like terms: -29 + 29 = 0
0 + 7c = -29 + 29 + c
7c = -29 + 29 + c

Combine like terms: -29 + 29 = 0
7c = 0 + c
7c = c

Solving
7c = c

Solving for variable 'c'.

Move all terms containing c to the left, all other terms to the right.

Add '-1c' to each side of the equation.
7c + -1c = c + -1c

Combine like terms: 7c + -1c = 6c
6c = c + -1c

Combine like terms: c + -1c = 0
6c = 0

Divide each side by '6'.
c = 0

Simplifying
c = 0